snowflake.snowpark.Column.name¶

Column.name(alias: str, variant: Literal['as_', 'alias', 'name'] = 'name') → Column[source] (https://github.com/snowflakedb/snowpark-python/blob/v1.30.0/snowpark-python/src/snowflake/snowpark/column.py#L1321-L1353)¶

Returns a new renamed Column.