snowflake.snowpark.functions.try_parse_json¶
- snowflake.snowpark.functions.try_parse_json(e: Union[Column, str]) Column[source] (https://github.com/snowflakedb/snowpark-python/blob/v1.35.0/src/snowflake/snowpark/functions.py#L6798-L6817)¶
Parse the value of the specified column as a JSON string and returns the resulting JSON document. Returns NULL if an error occurs during parsing.
- Example::