snowflake.snowpark.catalog.Catalog.getSchema

Catalog.getSchema(schema: str, *, database: Optional[Union[str, DatabaseModel]] = None) ModelSchemaModel[source] (https://github.com/snowflakedb/snowpark-python/blob/v1.29.1/snowpark-python/src/snowflake/snowpark/catalog.py#L334-L339)

Name of the schema to get.

Language: English