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snowflake.snowpark.WindowSpec.partitionBy

WindowSpec.partitionBy(*cols: Union[Column, str, Iterable[Union[Column, str]]]) WindowSpec[source] (https://github.com/snowflakedb/snowpark-python/blob/v1.16.0/src/snowflake/snowpark/window.py#L177-L198)

Returns a new WindowSpec object with the new partition by clause.

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