snowflake.snowpark.functions.parse_json¶ snowflake.snowpark.functions.parse_json(e: ColumnOrName) → Column[source] (https://github.com/snowflakedb/snowpark-python/blob/release-v1.1.0/src/snowflake/snowpark/functions.py#L2253-L2257)¶ Parse the value of the specified column as a JSON string and returns the resulting JSON document.