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snowflake.snowpark.Column.name¶

Column.name(alias: str, variant: Literal['as_', 'alias', 'name'] = 'name') → Column[source] (https://github.com/snowflakedb/snowpark-python/blob/v1.27.0/snowpark-python/src/snowflake/snowpark/column.py#L1317-L1343)¶: Returns a new renamed Column.